0.008x^2-3.2=0

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Solution for 0.008x^2-3.2=0 equation:



0.008x^2-3.2=0
a = 0.008; b = 0; c = -3.2;
Δ = b2-4ac
Δ = 02-4·0.008·(-3.2)
Δ = 0.1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.1024}}{2*0.008}=\frac{0-\sqrt{0.1024}}{0.016} =-\frac{\sqrt{}}{0.016} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.1024}}{2*0.008}=\frac{0+\sqrt{0.1024}}{0.016} =\frac{\sqrt{}}{0.016} $

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